最新公告 |
[DhtmlXQ] [DhtmlXQ_init]500,350[/DhtmlXQ_init] [DhtmlXQ_binit]9999999949999999999902999999992280109932314199999999997999999999[/DhtmlXQ_binit] [DhtmlXQ_title]趣味学残局之炮低兵对双士[/DhtmlXQ_title] [DhtmlXQ_movelist]2221313021111031112130400200405000804130213132418082796982026959493950510206415006095152095952423121304139384132591932411910415238395241213141321040425239495251400051520001324101415251414051524030525130205152202150413141[/DhtmlXQ_movelist] [DhtmlXQ_firstnum]0[/DhtmlXQ_firstnum] [DhtmlXQ_length]55[/DhtmlXQ_length] [DhtmlXQ_result]红胜[/DhtmlXQ_result] [DhtmlXQ_comment4]只能跃马[/DhtmlXQ_comment4] [DhtmlXQ_move_0_6_1]808721203040020031102010[/DhtmlXQ_move_0_6_1][DhtmlXQ_comment1_11]红胜[/DhtmlXQ_comment1_11][DhtmlXQ_comment23]这就形成了炮低兵对双士的残局,是必胜残局[/DhtmlXQ_comment23] [DhtmlXQ_move_0_36_2]425239494132101150411141[/DhtmlXQ_move_0_36_2][DhtmlXQ_comment37]逼离将位[/DhtmlXQ_comment37] [/DhtmlXQ]

本局最终演化成炮低兵对双士的残局,是必胜残局,取胜的要点在于首先逼离将位离开中路,进而限制黑将的活动,使其只能走士,形成炮换双士的局面。